Question

factorice a^3-3a^2b+3a^2-b^3​

Answer 1

Answer:

Step-by-step explanation:

A^3-3A^2B+3AB^2-2B^3

-> A^3-3A^2B+3AB^2-B^3-B^3

-> (A-B)^3-B^3

-> (A-B-B) {(A-B)^2+(A-B)B+B^2}

-> (A-2B) (A^2-2AB+B^2+AB-B^2+B^2)

-> (A-2B)(A^2-AB+B^2)

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Answer 2

Ans:

$a^3-3a^2b+3a^2-b^3\\= (a^3-b^3)+3a^2-3a^2b\\= (a^3-b^3)+3a^2(1-b)$

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