Factorice -: (x^2+x)^2+4(x^2+x)-12
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PulkitStar:
you too good answer...
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Hey there
The given equation =(x^2+x)^2+4(x^2+x)-12
Let x²+x=k
So ,the equation is kx²+4k-12
Now factorize the equation
k²-2k+6k-12
=k(k-2)+6(k-2)
= (k+6)(k-2)
There fore : (x²+x)²+4(x²+x)-12= (x²+x+6)(x²+x-2)
Now factorize x²+x-2
x²-x+2x-2
=x(x-1)+2(x-1)
=(x+2)(x-1)
There fore , (x^2+x)^2+4(x^2+x)-12=(x²+x+6)(x+2)(x-1)
Factors are
1)x²+x+6
2) (x+2)
3) (x-1)
hope helped!
The given equation =(x^2+x)^2+4(x^2+x)-12
Let x²+x=k
So ,the equation is kx²+4k-12
Now factorize the equation
k²-2k+6k-12
=k(k-2)+6(k-2)
= (k+6)(k-2)
There fore : (x²+x)²+4(x²+x)-12= (x²+x+6)(x²+x-2)
Now factorize x²+x-2
x²-x+2x-2
=x(x-1)+2(x-1)
=(x+2)(x-1)
There fore , (x^2+x)^2+4(x^2+x)-12=(x²+x+6)(x+2)(x-1)
Factors are
1)x²+x+6
2) (x+2)
3) (x-1)
hope helped!
No
Let me point it out
In the step where he says therefore he writes x^2 +x+6 then in the next step he makes it x^2+x-6 ......
There fore : (x²+x)²+4(x²+x)-12= (x²+x+6)(x²+x-2)
Now factorize x²+x-6 .....
Now factorize x²+x-6 .....
See how the x^2 +x+6 becomes x^2+x-6
Now say.......
thanks
i was in a hurry
don"t talk harshly..... he is a human and human only make mistakes.....
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