factoricze: (p-q)^3+(q-r)^3+(r-p)^3
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When Assume a = p-q , b = q-r , c= r-p
than a+ b+ c = 0 --> a³ + b³ + c³ = 3abc '
So, (p-q)³ + (q-r)³ + (r-p)³ = 3(p-q)(q-r)(r-p)
please give me brilliant answer please
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