Question

factorie : a2 + 16а – 80​

Answer 1

Step-by-step explanation:

Hope ,it helpful for you

Answer 2

$\underline{\textbf{QUESTION :-}}$

To Factorize : a² + 16а – 80​

$\underline{\textbf{ANSWER :-}}$

Given            : a² + 16а – 80​

To Factorize : a² + 16а – 80​

$a^2+16a-80$

$a^2-4a+20a-80$

$a(a-4)20(a-4)$

$(a+20)(a-4)$

$\boxed{\textsf{(a+20) (a-4)}}$

⇢ In this sum we used the method of Factorizing The Middle Term

• When splitting the middle term, our objective is to write quadratic expressions as the product of two linear polynomials.

• The method for factoring by splitting the middle term is shown in detail in the following tutorial, in which we factor various examples of quadratic expressions.

• Suppose you have a polynomial that can be factored as:

$\textsf{(Ax+B)(Cx+D)}$

Let's multiply this out and simplify the expression.

$\textsf{AC}$$x^2$ $\textsf{+(AD+BC)x+BD}$

So in terms of the form $ax^2+bx+c$ we have:

$\textsf{a=AC }$

$\textsf{b=AD+BC}$

$\textsf{c=BD}$

In these examples we will start from the quadratic expression:  

$\textsf{AC}$$x^2$ $\textsf{+(AD+BC)x+BD}$

And we will try to factor it back into the form:

$\textsf{(Ax+B)(Cx+D)}$

→The goal is to find some combination of factors of $\textsf{ABCD}$ that add up to $\textsf{b=AD+BC}$