Question

factorie by splliting middle term y^2-4y+3​

Answer 1

Answer:

(y-1)(y-3)

Step-by-step explanation:

${y}^{2} - 4y + 3 \\ = {y}^{2} - (3 + 1)y + 3 \\ = {y}^{2} - 3y - y + 3 \\ = y(y - 3) - 1(y - 3) \\ = (y - 1)(y - 3)$

Answer 2

${y}^{2} -4y+3 = 0$

${y}^{2}-3y-y +3 = 0$

$y ( y -3) -1(y-3) = 0$

$(y -1) ( y-3) = 0$

Here,taking $y -1 = 0$

we get,

$y = 1$

and taking $y-3 = 0$

we get,

$y = 3$