Factorie polynomial 2y^2+27y+13=0
Answers
Answered by
0
Answer:
(2y+1) (y+13) answer
Step-by-step explanation:
= 2y^2+27y+13=0
= 2y^2+(26+1)y+13=0
= 2y^2+26y+y+13=0
= 2y(y+13) +1(y+13)=0
= (2y+1) (y+13) answer
I hope it is useful for you so plz mark me as brainliests and give thanks
Similar questions