Factorie x3 - 8x2 17 x 10
RevelliSowmya422:
mention the signs properly..........
Answers
Answered by
3
HEY!!
(x+1) is a factor of this because is exactly divisible by it.
for find other factor we divide x3-8x2+17x-10
and we find x2-7x+10
(x-1) (x2-7x+10)
(x-1)(x2-2x-5x+10)
(x-1) {x(x-2)-5(x-2)}
Ans) (x-1) (x-2) (x-5)
(x+1) is a factor of this because is exactly divisible by it.
for find other factor we divide x3-8x2+17x-10
and we find x2-7x+10
(x-1) (x2-7x+10)
(x-1)(x2-2x-5x+10)
(x-1) {x(x-2)-5(x-2)}
Ans) (x-1) (x-2) (x-5)
Answered by
5
x^3 - 8x^2 +17x - 10
[ Break - 8x^2 as - x^2 - 7x^2]
[ Break 17x as 7x + 10x]
= x^3 - x^2 - 7x^2 +7x + 10x - 10
= x^2 ( x - 1) - 7x ( x - 1) + 10(x-1)
= ( x - 1) ( x^2 - 7x + 10)
= (x - 1) x^2 - 2x - 5x + 10)
= ( x - 1) [ x (x - 2) - 5(x - 2)]
= (x-1) (x - 2)(x - 5)
[ Break - 8x^2 as - x^2 - 7x^2]
[ Break 17x as 7x + 10x]
= x^3 - x^2 - 7x^2 +7x + 10x - 10
= x^2 ( x - 1) - 7x ( x - 1) + 10(x-1)
= ( x - 1) ( x^2 - 7x + 10)
= (x - 1) x^2 - 2x - 5x + 10)
= ( x - 1) [ x (x - 2) - 5(x - 2)]
= (x-1) (x - 2)(x - 5)
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