Question

Factories

1)2x²+3x-2
2)2x²(x+y)-3(x+y)
3)x³-2x²y+3xy²-6y³​

Answer 1

Solution

Given : x

3

−2x

2

y+3xy

2

−6y

3

By taking x

2

as common in the first two term and 3y

2

as common in the second two term

x

3

−2x

2

y+3xy

2

−6y

3

=x

2

(x−2y)+3y

2

(x−2y)

So we get,

x

3

−2x

2

y+3xy

2

−6y

3

=(x−2y)(x

2

+3y

2

)