Question

factories 14-5a-a^2 by using the method of middle term factorisation (show step by step)​

Answer 1

Step-by-step explanation:

First,

convert the given equation in the form of quadratic equation

Given

= 14-5a-a² Or it can be written as by taking out - sign common

that is -(a²+5a-14) Here a is working for x

Quadratic equation = ax²+bx+c

Now compare the given equation with the quadratic equation

here we will write the coefficients of x² and x

where we get a= 1

b=5

c=-14

Now by middle term splitting method we get

= -(a²+5a-14)

= -( a²+7a-2a -14)

= -( a(a+7)-2( a+7))

= -(a-2)(a+7)

= (-a+2)(a+7)

where a= 2 and -7

Hope this helps you