Question

Factories 15x2 + 19x + 6​

Answer 1

$\huge\bf{Answer :}$

$\huge{\boxed{x = \frac{-3}{5}}}$ OR $\huge{\boxed{x = \frac{-2}{3}}}$

$\huge\bf{Explanation : }$

Given Equation :

$15 {x}^{2} + 19x + 6$

Solution :

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 15 {x}^{2} + 19x + 6 = 0 \\ \: \: \: \: \: \: \: 15 {x}^{2} + 10x + 9x + 6 = 0 \\ (15 {x}^{2} + 10x) + (9x + 6) = 0 \\ \: \: 5x(3x + 2) + 3(3x + 2) = 0 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (5x + 3)(3x + 2) = 0 \\ (5x + 3 = 0) \: or \: (3x + 2) = 0$

$\huge{\boxed{x = \frac{-3}{5}}}$ OR $\huge{\boxed{x = \frac{-2}{3}}}$

Answer 2

Step-by-step explanation:

15x² + 19x + 6

15x² + 10x + 9x + 6

5x(3x + 2) + 3(3x + 2)

(5x + 3) (3x + 2)