Question

factories 16x²_8x+1​

Answer 1

Question:-

$16 {x}^{2} - 8x + 1 = 0$

Answer is:-

$16 {x}^{2} - 4x - 4x + 1 = 0$

$4x(4x - 1) - 1(4x - 1) = 0$

$(4x - 1)(4x - 1) = 0$

$x = \frac{1}{4} \: \: and \: \: x = \frac{1}{4}$

Here, is the required Answer.

Hope it helps you dear.......xd