Question

Factories
216+27b^3+8c^3_108bc

Answer 1

Step-by-step explanation:

$= 216 + {27b}^{3} + {8c}^{3} - 108bc \\ = {(6)}^{3} + {(3b)}^{3} + {(2c)}^{3} - 3 \times 6 \times (3b) \times (2c) \\ \\ we \: know \: that \\ = {a}^{3} + {b}^{3} + {c}^{3} - 3abc \\ where \: \\ a = 6 \\ b = 3b \\ c = 2c \\ = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca \\ \\ = (6 + 3b + 2c)( {6}^{2} + {(3b)}^{2} + {(2c)}^{2} -6 \times 3b - 3 b\times 2c - 2c \times 6 ) \\ = (6 + 3b + 2c)(36 + 9 {b}^{2} + 4 {c}^{2} - 18b - 6bc - 12c )$

Hope this is help for you....

Answer 2

Step-by-step explanation:

216 + 27b*3 + 8c*3 - 108bc

( 6 )*3 + ( 3b )*3 + ( 2c )*3 - 3 × 6 × 3b × 2c

we know that

a*3 + b*3 + c*3 - 3abc

(a+b+c) (a*2+b*2+c*2-ab-bc-ca)

(6+3b+2c[(6)*2+(3b)*2+(2c)*2-(6×3b)-(3b×2c) -(2c×6)]

(6+3b+2c) [36+9b*2+4c*2-18b-6bc-12c ]