Factories 24a3+81b3 what is the answer to this question
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0
Answer:
Let us know some algebraic identity formulas before solving the problem:
(xy) x22xy+y (x-y)2 x2- 2xy+y (xy)3x3 3x3y 3xy (x- y)3x3 - 3xy 3xy2-y x2 +y?
(xy) (x- xy+y? x3- y?=(x- y) (x+ xy+ y y3 + Solution: Now, 24a3 81b3 3 (8a3 +27b3 =3 [ (2a)3 +(3b) -3 (2a 3b) (2a) - (2a x 3b) (3b) =3 (2a 3b) (4a - 6ab 9b2),
Answered by
1
Answer:
We know that,
a³ + b³ = (a + b) (a² – ab + b²)
24a3 + 81b3 = 3 [(2a)³ + (3b)³] [By taking out the common factor 3]
Here, a = 2a and b = 3b
Now, substituting in the above formula, we get
3 [(2a)³ + (3b)³] = 3 {(2a + 3b) [(2a)² – (2a)(3b) + (3b)²]}
= 3(2a + 3b) (4a² – 6ab + 9b²)
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