Question

factories 25a2-4b²+28bc-49c2​

Answer 1

Step-by-step explanation:

Answer: The factorized form will be

(5a+2b-7c)(5a-2b+7c)

Step-by-step explanation:

Since we have given that

25a^2-4b^2+28bc-49c^2

We need to factorise the above expression:

25a^2-4b^2+28bc-49c^2\\\\=25a^2-(4b^c-28cbc+49c^2)\\\\=25a^2-((2b)^2-2\times 2b\times 7c+(7c)^2)\\\\=(5a)^2-(2b-7c)^2\\\\\text{ Using identity: }a^2-b^2=(a+b)(a-b)\\\\=(5a+2b-7c)(5a-(2b-7c))\\\\=(5a+2b-7c)(5a-2b+7c)

Hence, the factorized form will be

(5a+2b-7c)(5a-2b+7c)

Answer 2

Answer:

5a whole square, - 2bwhole square,+7×4th - 7c whole square,