Factories 27x3+y3+z3-9xyz
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Answer:
(3x+y+z)(9x ^2 +y^2+z ^2 −3xy−yz−3zx).
Step-by-step explanation:
27x^3 + y^3 +z^3 −9xyz
=(3x)^3 +y^3 +z^ 3 −9xyz
=(3x)^3+y^3 +z^3 −3×3x×y×z
using identity
a^3 +b^3 +c^3 −3abc = (a+b+c)(a^2 +b^ 2+c^2−ab−bc−ca)
Putting a = 3x, b = y, c = z
= (3x+y+z)(9x ^2 +y^2+z ^2 −3xy−yz−3zx).
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