Factories:- (2x+3y)²-(2x+3y)-6
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Answer:
Let (2x + 3y) = a
∴ (2x + 3y)2 = a2
∴ 1 – (2x + 3y) – 6 (2x + 3y)2
= 1 – a – 6a2
= 1 – 3a + 2a – 6a2
= 1(1 – 3a) + 2a (1 – 3a)
= 1(1 – 3a) (1 + 2a)
= [1 – 3(2x + 3y)] [1 + 2(2x + 3y)]
(Substituting the value of a)
= (1 – 6x – 9y) (1 + 4x + 6y)
hope it helps you...☺️
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