Math, asked by bedi38005, 8 months ago

factories (2x+3y)^3-(2x-3y)^3​

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Answered by mjha79706
3

Answer:

hope it helpss

Step-by-step explanation:

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Answered by ishwarsinghdhaliwal
1

 = ( {2x})^{3}  + ( {3y})^{3}  + 3 ({2x})^{2} (3y) + 3(2x)( {3y})^{2}  \\   - [ ( {2x})^{3}  + ( { - 3y})^{3}  + 3 ({2x})^{2} ( - 3y) + 3(2x)( { - 3y})^{2} ] \\  =  {8x}^{3}  +  {27y}^{3}  + 36 {x}^{2} y + 54x {y}^{2} - [ {8x}^{3}  - 27 {y}^{3}  -36 {x}^{2} y + 54xy^{2} ] \\  = {8x}^{3}  +  {27y}^{3}  + 36 {x}^{2} y + 54x {y}^{2} -  {8x}^{3}   + 27 {y}^{3}   + 36 {x}^{2} y  - 54xy^{2}  \\  = 54 {y}^{3}  + 72 {x}^{2} y \\  = 18y(3y ^{2}  + 4 {x}^{2} )

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