Math, asked by Shameer1, 1 year ago

Factories. 2y³ + y² - 2y -1

Answers

Answered by Anonymous
36
2y³ + y² - 2y -1

= 2y^3 - 2y + y^2 - 1

= 2y(y^2 - 1) +1(y^2 - 1)

= (2y+1) ( y^2 - 1)

= (2y+1) ( y^2 - 1^2)

= (2y+1) ( y+1) ( y-1)

Hope it's helpful to u.
Answered by lakhipriyadas1
24
Hope the answer is helpful......
Attachments:

lakhipriyadas1: No.. my answer is completely correct
Anonymous: y-1 instead of y+1
Anonymous: check last step
lakhipriyadas1: Ooo yeah
lakhipriyadas1: Symbol is wrong..
Anonymous: hmm
lakhipriyadas1: Am I right
Anonymous: (y-1)(y+1)(2y+1).. u r also correct
Shameer1: thank you very much
lakhipriyadas1: Welcome
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