Question

Factories: 3a(x²×y²) +6b (x²×y²​

Answer 1

Answer:

3a(x

2

+y

2

)+6b(x

2

+y

2

)

Take out common in both terms,

Then, 3(x

2

+y

2

)(a+2b)

Therefore,HCF of 3a(x

2

+y

2

)and6b(x

2

+y

2

)is3(x

2

+y

2

).

Answer 2

3a ( x ² × y ² ) + 6b ( x ² × y² )

solution

3a ( ax ² y ² + 2bx ² y² )

x ²y ² ( a + 2b )

3x²y² ( a + 2b )