Question

Factories 3a²+4ab+b²-2ac-c²​

Answer 1

Write 3a2+4ab+b2−2ac−c2

3a2+4ab+b2−2ac−c2 as 4a2+4ab+b2−a2−2ac−c2

3a2+4ab+b2−2ac−c2 as 4a2+4ab+b2−a2−2ac−c2 = (2a+b)2−(a+c)2

3a2+4ab+b2−2ac−c2 as 4a2+4ab+b2−a2−2ac−c2 = (2a+b)2−(a+c)2 = (2a+b+a+c).(2a+b−a−c) [Since A2−B2=(A−B).(A+B) ]

3a2+4ab+b2−2ac−c2 as 4a2+4ab+b2−a2−2ac−c2 = (2a+b)2−(a+c)2 = (2a+b+a+c).(2a+b−a−c) [Since A2−B2=(A−B).(A+B) ]= (3a+b+c).(a+b−c)

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