Math, asked by parthop14, 2 days ago

factories 3x^3-3x^2-42x+72 by using factor theoram​

Answers

Answered by ddong
0

Answer:

(x - 2)(x - 3)(x + 4)

Step-by-step explanation:

 {3x}^{3}  -  {3x}^{2}  - 42x + 72 =  {x}^{3}  - {x}^{2}  - 14x + 24

Using the factor theorem, it can be factored into (x-2)(x-3)(x+4)

Answered by mukkeraabhishek
1

Answer:

3 {x}^{3} - 3 {x}^{2} - 42x + 72 = 3(x - 2)(x + 4)(x - 3)3x

3

−3x

2

−42x+72=3(x−2)(x+4)(x−3)

Step-by-step explanation:

I hope it is helpful to you

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