Question

factories:3x^3-x^2-3x+1 using and long division​

Answer 1

Answer:

(3x-1)(x+1)(x+1)

Step-by-step explanation:

let, f(x)=3x^3-x^2-3x+1

by remainder theorem,

assume, we put value of x=1

f(x)=3(1)^3-(1)^2-3(1)+1

f(x)=3-1-3+1

f(x)=0

hence, the g(x) of f(x) is x-1

by long division method,

=3x^3-x^2-3x+1÷x-1

=3x^2+2x-1

then,

=3x^2+2x-1

=3x^2+3x-x-1

=3x(x+1)-1(x+1)

therefore,the factors of f(x) are (3x-1) ,(x+1) and (x-1)