Question

factories :√3x2+4x+√3
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Answer 1

$\sqrt{3} {x}^{2} + 4x + \sqrt{3}$

$= \sqrt{3} {x}^{2} + 3x + x + \sqrt{3}$

$= \sqrt{3}x(x + \sqrt{3}) + 1(x + \sqrt{3})$

$= ( \sqrt{3}x + 1)(x + \sqrt{3})$

Hence,

$x = \frac{ - 1}{ \sqrt{3} } \: and \: x = - \sqrt{3}$

This is the required answer.

Answer 2

Answer:

√3x2 + 4x + √3

√3x2 + 3x + x + √3

= √3x ( x + √3 ) + 1 ( x + √3 )

= ( √3x + 1 ) ( x + √3 )

= √3x = -1

= x = -1/√3

= x= -√3

therefore, x = -1/√3 , -√3

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