Question

Factories 5 root 5 x² +20x + 3 root5 please give me quickly ​

Answer 1

Step-by-step explanation:

Given-5√5x^2+20x+3√5=0

we need to factorize this so,

Step one:Find product of coefficient of x^2 and constant value,

5√5*3√5=75

Step two:Break coefficient of 20x such that the two parts when multiplied we get 75

20x=15x+5x (15*5=75)

so we take 15x and 5x

then in the equation,

5√5x^2+5x+15x+3√5=0

taking 5x common from 5√5x^2+5x and 3√5 common from 15x+3√5

5x(x√5+1)+3√5(x√5+1)=0

(x√5+1)(5x+3√5)=0

At this step we can take out √5 common from (5x+3√5) then,

(x√5+1)√5(√5x+3)=0

(x√5+1)(x√5+3)=0