Question

factories 6-24(x-y) 2

Answer 1

$Given \:6 - 24(x-y)^{2} \\= 6[1 - 4(x-y)^{2}]\\= 6[1^{2} - \Big(2(x-y)\Big)^{2} ]\\= 6[1^{2} - (2x-2y)^{2}]\\= 6[1+(2x-2y)][1-(2x-2y)]$

$\boxed { \pink { Since, a^{2}-b^{2} = (a+b)(a-b) }}$

$= 6( 1 + 2x - 2y )( 1 - 2x + 2y )$

Therefore.,

$\red{ 6 - 24(x-y)^{2}}\green { = 6( 1 + 2x - 2y )( 1 - 2x + 2y )}$

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