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64-(a +12)^2
What will be the process of this question?
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Answer:
64-(a^2+144+2×12×a)=0
64-a^2-144+24a=0
0=a^2-24a+144-64
0=a^2-24a+80
0=a^-20a-4a+80
0=a (a-20)-4 (a-20)
0=(a-4)(a-20)
a=4
Or
a=20
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