Question

factories 6x^2- 13x +6​

Answer 1

Answer:

$6x^2 - 13x + 6 = (3x-3) (2x - 3)$

Step-by-step explanation:

If the equation is in the format  of $ax^2 + bc + c$

Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.

Step 2: Rewrite the middle with those numbers.

Step 3: Factor the first two and last two terms separately

$6x^2 - 13x + 6$

Now ac = 6 × 6 = 36

Find factor of 36 whose product is 36 and sum is -13

Two number are -9, -4

So,

$6x^2 - 13x + 6 = 6x^2 - 9x- 4x + 6\\= 3x ( 2x - 3) - 2 (2x - 3)\\= (3x-3) (2x - 3)$

Answer 2

Answer:

On factorizing $6x^{2} -13x + 6$ we get factors , $( 3x - 2 ) (2x - 3)$ .

Step-by-step explanation:

To factorize : $6x^{2} -13x + 6$

Solution :

• According to question we are asked to factorize the given expression
• We factorize expression ,  $6x^{2} -13x + 6$ by splitting the middle term .  

• We spilt the middle term such that product of the numbers is last term and sum or difference of those numbers is middle term.
• Here, $13x$ is the middle term and by multiplying constants of first term and last we get $36$ as the last term.

        $6x^{2} -13x + 6 \\\\= 6x^{2} -9x-4x + 6\\\\= 3x ( 2x - 3 ) -2 ( 2x -3 ) \\\\= ( 3x -2 ) ( 2x - 3 )$