Question

Factories:-
6x2+7√2x+4

Answer 1

Hello!!!

$6x{}^{2}+7\sqrt{2x}+4$

$6x{}^{2}+4\sqrt{2}x+3\sqrt{2}x+4$

$2x(3x+2\sqrt{2})+\sqrt{2}(3x+2\sqrt{2})$

$(3x+2\sqrt{2})(2x+\sqrt{2}$

Hope it's help uh

Answer 2

Answer:

$x = \frac{ - 1}{ \sqrt{2} } \: \: \: or \: \: \: \frac{ - 4}{3 \sqrt{2} }$

Step-by-step explanation:

$6 {x}^{2} + 7 \sqrt{2} x + 4 \\ \\ 6 {x}^{2} + 3 \sqrt{2} x + 4 \sqrt{2} x + 4 \\ \\ 3 \sqrt{2} x( \sqrt{2} x + 1) + 4( \sqrt{2} x + 1)$

$( \sqrt{2} x + 1)(3 \sqrt{2} x + 4)$

Now ,

put

$\sqrt{2} x + 1 = 0 \: \: or \: \: 3 \sqrt{2} x + 4 = 0$

$therefore \: \: \: \\ \\ x = \frac{ - 1}{ \sqrt{2} } \: \: or \: \: \frac{ - 4}{3 \sqrt{2} }$