Question

Factories - 6x² - 7 √3x - 15

Answer 1

Answer:

STEP

1

:

Equation at the end of step 1

((2•3x2) + 3x) - 15 = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

6x2 + 3x - 15 = 3 • (2x2 + x - 5)

Trying to factor by splitting the middle term

3.2 Factoring 2x2 + x - 5

The first term is, 2x2 its coefficient is 2 .

The middle term is, +x its coefficient is 1 .

The last term, "the constant", is -5

Step-1 : Multiply the coefficient of the first term by the constant 2 • -5 = -10

Step-2 : Find two factors of -10 whose sum equals the coefficient of the middle term, which is 1 .

-10 + 1 = -9

-5 + 2 = -3

-2 + 5 = 3

-1 + 10 = 9

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

3

:

3 • (2x2 + x - 5) = 0

STEP

4

:

Equations which are never true

4.1 Solve : 3 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Answer 2

Step-by-step explanation:

6x²-7√3x-15

6x²(10-3)√3-15

6x²- 10√3x +3√3x -15

2√3x (√3x-5) +3(√3x-5)

(2√3x+3)(√3x-5)