Math, asked by divi280107, 7 months ago

Factories: 7√2k^2-10k-4√2
pls answer it fast​

Answers

Answered by manasvis2005
3

Hey there,

Refer to the attachment provided.

Attachments:
Answered by Anonymous
3

Solution:-

  • Factorisation Method

7√2 k² - 10k - 4√2 = 0

7√2 k² - 14k + 4k - 4√2 = 0

7k(√2 k - 2) + 2√2(√2 k - 2) = 0

(7k + 2√2) (√2 k - 2) = 0

(7k + 2√2) = 0 or (√2 k - 2) = 0

7k = -2√2 or √2 k = 2

k = -2√2/7 or k = 2/√2

k = 2/√2 × √2/√2

k = 2√2/2

k = √2

Note:- [ 4√2 × 7√2 = 28 × 2 = 56 = 14 × 4. If sum and product both are in minus then it is written as -14k + 4k ]

More information:-

If product of two numbers is zero then at least one of them is zero.

•°• x - 5 = 0 or x + 1 = 0

•°• x = 5 or x = -1

•°• 5 and the -1 are the roots of the given quadratic equation.

While solving the equation first we obtained the linear factors. So we call this method as ’factorization method’ of solving quadratic equation

Quadratic equation can also be solved by Factorization, formula method and completing the square method.

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