Question

factories 7x^3 + 56 y^3​

Answer 1

Answer:

7[(x+2y) (x²-2xy+4y²) ]

Explanation:

Pull out like factors :

7x3 + 56y3 = 7 • (x3 + 8y3)

Factoring: x3 + 8y3

Theory : A sum of two perfect cubes, a3 + b3 can be factored into :

(a+b) • (a2-ab+b2)

Proof : (a+b) • (a2-ab+b2) =

a3-a2b+ab2+ba2-b2a+b3 =

a3+(a2b-ba2)+(ab2-b2a)+b3=

a3+0+0+b3=

a3+b3

Check : 8 is the cube of 2

Check : x3 is the cube of x1

Check : y3 is the cube of y1

Factorization is :

(x + 2y) • (x2 - 2xy + 4y2)

therefore, 7[(x+2y) (x²-2xy+4y²) ] is the answer

hope it helps

Answer 2

question

7x³+56y³

Answer

= 7x³+56³ = 7(x³+8y³)

= 7[(x+2y)(x²- 2xy + 4y²)]

= therefore 7(x+2y)(x²-2xy+4y²). answer