factories -8+6y+2y^2
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2y^2 +6y-8
2y^2+8y-2y-8
2y(y+4)-2(y+4)
(2y-2)(y+4) = 0
y=1 or -4
Answered by
0
2y²+6y-8=0
2y²+8y-2y-8 = 0
2y(y+ 4)-2(y+4) =0
(2y-2)(y+4)=0
y = 1,-4
2y²+8y-2y-8 = 0
2y(y+ 4)-2(y+4) =0
(2y-2)(y+4)=0
y = 1,-4
akahitasingh12:
hi
its ok
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