Question

factories 8a3-27b3-8c3-36abc

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Answer 1

Answer:

8a^3-27b^3-8c^3-36abc

=→ As we know a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-2ab-2bc-2ca)

So,

it will be :→

(2a)^3-(3b)^3-(2c)^3-(3×12)abc

=(2a-3b-2c){(2a)^2-(3b)^2-(2c)^2-2×2a×(-3b)-2×

(-3b)×(-2c)-2×(-2c)×2a}

=(2a-3b-2c)(4a^2-9b^2-4c^2+12ab-12bc+8ac)

Step-by-step explanation:

Hope it works.....