Question

factories a² + bc + ab + ac = ? ​

Answer 1

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factories a² + bc + ab + ac

$\huge{\mathcal{\underline{\red{AnSWeR}}}}$

a²+bc+ab+ac

Rearrange them

a²+ab+ac+bc

(a×a+a×b)+(a×c+b×c)

Take common

a(a+b)+c(a+b)

(a+c)(a+b)

Hence factorized

Answer 2

Answer:

a² + bc + ab + ac

Rearranging the terms , we get

= a² + ab + ac + bc

= ( a×a + a×b )+( a×c+b×c )

Take a and c common in

first and second brackets

respectively, we get

= a( a + b ) + c( a + b )

Again take ( a + b )

common , we get

= ( a + b )( a + c )