factories ab minus 3b plus 3c minus ac
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We have,
ab-3b +3c-ac
Solving this further by taking variables in common,
b(a-3) +c(3-a)
Taking -ve for the sake of taking common terms.
= b(a-3) -c(a-3)
=(a-3)(b-c)
ab-3b +3c-ac
Solving this further by taking variables in common,
b(a-3) +c(3-a)
Taking -ve for the sake of taking common terms.
= b(a-3) -c(a-3)
=(a-3)(b-c)
Answered by
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