Question

factories by regrouping 1+a²b²+a²+b²​

Answer 1

here is your answer:

$( {a}^{2} {b}^{2} + {b}^{2}) + ( {a}^{2} + 1) \\ = {b}^{2}( {a}^{2} + 1) + 1( {a}^{2} + 1) \\ = ( {a}^{2} + 1)( {b}^{2} + 1).$

hope its helpful !