Math, asked by gopikantht, 11 months ago

factories by splitting the middle term x²+6×-16​

Answers

Answered by Anonymous
1

\mathsf{x^{2} + 6x - 16}

\mathsf{\rightarrow\: x^{2} - 2x + 8x - 16}

\mathsf{\rightarrow\: x( x - 2) + 8(x - 2)}

\mathsf{\rightarrow\: (x + 8) (x - 2)}

\mathsf{\rightarrow\: \red{x = 2} \:\: ; \:\: \green{x = - 8}}

Explaination

  • Multiply the coefficient of x² and the constant term

  • Split the middle term into two terms such that their product is equal to the product of coefficient of x² and the constant term

  • Split the middle term in two terms such that on adding them, we get the coefficient of x
Answered by Anonymous
4

Answer:

x^2+6x-16=0

(x-2)(x+8)=0

thanks!!

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