Question

factories each of the following expression : (i)x³+125​

Answer 1

Answer:

hii sorry I didn't know ans-......

Answer 2

Answer:

Factor x3 – 125 as (a – b)(a2 + ab + b2), substituting a = x and b = 5 into the expression. Square the first and last terms, and rewrite (x)(5) as 5x. Let's see what happens if you don't factor out the common factor first. In this example, it can still be factored as the difference of two cubes.