Question

factories full this question

Answer 1

heya dear frnd here is your answer
y^2(2y+1)-1(2y+1)
2y+1,y^2-1
2y=-1,y=-1/2
y^2=1,y=√1

Answer 2

$2y ^{3} + {y}^{2} - 2y - 1$
$= {y}^{2} (2y + 1) - 1(2y + 1)$
$= (2y + 1)( {y}^{2} - 1)$
$= (y + 1)(y - 1)(2y + 1)$