factories it
(4y-5)²+80y
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Answered by
0
Answer:
(4y-5)* 2 +80y
(4y-5)*2+80y
=16y*2+40y 25
=(4y+5)*2
Answered by
2
Answer: PLEASE BRAINLIEST MY ANSWER
factors of (4y-5)²+80y are (4y+5)(4y+5)
Step-by-step explanation:
Q) Factories it (4y-5)²+80y
⇒ (4y-5)²+80y = (4y)² - 2*(4y)*5 + 5² + 80y-----[(ax+b)²=(ax)²+2abx+b²]
= 16y² - 40y + 25 + 80y
= 16y² - 40y + 80y + 25
= 16y² + 40y + 25
= 16y² + 20y + 20y + 25
= 4y(4y+5) + 5(4y+5)
(4y-5)²+80y = (4y+5)(4y+5)
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