Math, asked by rushabsanjaygandhi, 7 months ago

factories it
(4y-5)²+80y

Answers

Answered by shahmeena304
0

Answer:

(4y-5)* 2 +80y

(4y-5)*2+80y

=16y*2+40y 25

=(4y+5)*2

Answered by chetanakhairnar2000
2

Answer: PLEASE BRAINLIEST MY ANSWER

factors of (4y-5)²+80y are (4y+5)(4y+5)

Step-by-step explanation:

Q) Factories it  (4y-5)²+80y

⇒ (4y-5)²+80y  = (4y)² - 2*(4y)*5 + 5² + 80y-----[(ax+b)²=(ax)²+2abx+b²]

                        = 16y² - 40y + 25 + 80y

                        = 16y² - 40y + 80y + 25

                        = 16y² + 40y + 25

                        = 16y² + 20y + 20y + 25

                        = 4y(4y+5) + 5(4y+5)

  (4y-5)²+80y  = (4y+5)(4y+5)

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