factories it fast plz it is very important
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8a³+b³+27c³-18abc
=> (2a)³ + b³ + (3c)³ - 3 (2a)(b)(3c)
=> we know that , a³+b³+c³-3abc = ( a+b+c ) ( a²+b²+c²-ab-bc-ca )
=> ( 2a )³ + (b)³ + ( 3c )³ - 3 (2a)(b)(3c)
here , a = 2a
b = b
c = 3c
then ,
=> ( 2a+b+3c ) ( 4a²+b²+9c²-2ab-3bc-6ac )
=> ( 2a+b+3c ) ( 4a²+b²+9c² - 2ab-3bc-6ac )
is the answer
hope this helps
=> (2a)³ + b³ + (3c)³ - 3 (2a)(b)(3c)
=> we know that , a³+b³+c³-3abc = ( a+b+c ) ( a²+b²+c²-ab-bc-ca )
=> ( 2a )³ + (b)³ + ( 3c )³ - 3 (2a)(b)(3c)
here , a = 2a
b = b
c = 3c
then ,
=> ( 2a+b+3c ) ( 4a²+b²+9c²-2ab-3bc-6ac )
=> ( 2a+b+3c ) ( 4a²+b²+9c² - 2ab-3bc-6ac )
is the answer
hope this helps
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