Math, asked by niharb264, 10 months ago

factories it pls 1st answer will be brain liest​

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Answered by ItzAditt007
1

AnswEr:-

Given polynomial:-

\tt\longrightarrow 21{x}^{2}  - 2x +  \dfrac{1}{21} .

And we have to factorize it.

Now,

Let us factorize it by factorization method.

\\ \rm\longrightarrow Coefficient\ \ of\ \ x^2\times Constant\ \ Term. \\ \\ \tt = \cancel{21}\times \dfrac{1}{\cancel{21}}. \\ \\ \tt = 1. \\ \\ \rm Also, \\ \\ \tt\longrightarrow 1 = 1\times 1. \\ \\ \rm And, \\ \\ \tt\longrightarrow 1 + 1 = 2 = \rm Middle\ Term.\\

So,

Lets split the middle term:-

 \\ \tt\mapsto21 {x}^{2} - 2x +  \dfrac{1}{21}  . \\  \\ \\  \tt\mapsto21 {x}^{2}  - (1 + 1)x +  \frac{1}{21} . \\  \\  \\ \tt\mapsto21 {x}^{2}  - x - x +  \frac{1}{21}. \\  \\  \\  \tt\mapsto x(21x - 1)  -  \frac{1}{21} (21x - 1). \\  \\  \\ \tt\mapsto\underline{\underline{(x -  \frac{1}{21} )( 21x - 1).}} \\

\rule{200}2

We can also find out the solution of this.

For this it will be equal to zero.

\\ \tt\leadsto(x -  \dfrac{1}{21} )(21x - 1) = 0. \\  \\  \\ \tt\leadsto x - \frac{1}{21} = 0\ \  \:  \: or \:  \:  \:  \: 21x - 1 = 0. \\  \\  \\ \tt\leadsto \underline{\underline{x =  \frac{1}{21} \:  \:  \:  \: or \:  \:  \:  \: x =  \frac{1}{21}. }}\\

\rule{200}2

Answered by pinjaraarifisha
1

Answer:

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