factories:(p + q) square - 20(p + q) - 125
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Answered by
4
Answer:
Step-by-step explanation:
let (p+q)=x
now,
x²-20x-125
x²+5x-25x-125
x(x+5)-25(x+5)
(x+5)(x-25)
now putting the value of x
((p+q)+5)((p+q)-25)
(p+q+5)(p+q-25)
akshat4636123123:
thankss
Answered by
1
first let (p+q) be 'a'
now,
a
now putting the value of 'a'
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