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Solution
verified
Verified by Toppr
Given : x
3
−2x
2
y+3xy
2
−6y
3
By taking x
2
as common in the first two term and 3y
2
as common in the second two term
x
3
−2x
2
y+3xy
2
−6y
3
=x
2
(x−2y)+3y
2
(x−2y)
So we get,
x
3
−2x
2
y+3xy
2
−6y
3
=(x−2y)(x
2
+3y
2
)
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