Question

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$4 \sqrt{5} {x }^{2} + 7x - 3 \sqrt{5 } = 0$
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Answer 1

Step-by-step explanation:

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Answer 2

4√5x²+7x–3√5= 0. 4√5× 3√5= 12×5=60

4√5x²+12x–5x–3√5=0

4x(√5x + 3 ) – √5(√5x+3) =0

(√5+3)(4x–√5)=0