Question

factories the following 4x^2+2y^2+x^2y^2+8​

Answer 1

4x² + 2y² + x²y² + 8

Taking 4 common from 4x² and 8 & Taking y² common from 2y² and x²y² ,

We get ,

=> 4 ( x² + 2 ) + y² ( 2 + x² )

=> ( x² + 2 )( y² + 4 ) ..... Is the answer