Question

factories the following: a³-27​

Answer 1

Answer:

(a-3)(a²+3²+3a)

hope it helps

Step-by-step explanation:

Answer 2

Answer:

The value of a is 3.

Step-by-step explanation:

Given-

$a^{3} -27$

To find-

Factories $a^{3} -27$

Solution-

Factorising is a way of writing an expression as a product of its factors using brackets.

$a^{3} -27$

Shift -27 to right it becomes +27

$a^{3} =27$

We have to find the cube root of 27

$a=\sqrt[3]{27}$

27 is a cube of 3

$a=3$

The value of a is 3.

So, we can write it as

$(a-3)(a-3)^{2}$

= $(a-3)(a^{2}+9-6a)$