Math, asked by rajeshkkr008, 16 days ago

factories the following by taking out the common factor: 4x^2y^3 - 6x^3y ^2 - 12xy^2 .

Answers

Answered by sagarde409
0

Answer:

(2xy^{2}) (2xy-3x^{2} -6)

Step-by-step explanation:

Given, 4x^{2}y^{3}-6x^{3}y^{2} -12xy^{2}4x2y3−6x3y2−12xy2

=(2xy^{2}) (2xy-3x^{2} -6)=(2xy2)(2xy−3x2−6)

are the factors

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