Question

factories the following by taking out the common factor: 4x^2y^3 - 6x^3y ^2 - 12xy^2 .
​

Answer 1

Answer:

2x(y)^2 ( 2xy - 3(x)^2 - 6 )

Step-by-step explanation:

taking 2x(y)^2 common

2x(y)^2 ( 2xy - 3(x)^2 - 6 )

Answer 2

2xy² ( 2xy + 3x² - 6 )

You just have to divide it .....