Math, asked by adityarvs6464, 9 months ago

factories the following cubic polynomial
P(x) = x^3 - 4x^2+5x-2

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Answered by Anonymous

Answer:

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$for \: cubic \: polynomial \\ \\ p(x) = {x}^{3} - 4 {x}^{2} + 5x - 2 = 0 \\ \\ sum \: of \: zeros \: = \frac{ - b}{a} = \frac{ - (- 4)}{1} = + 4 \\ \\ sum \: of \: zeros \: = 4 \\ \\ product \: of \: zeros \: = \frac{ - d}{a} = \frac{ - (- 2)}{1} \\ \\ product \: of \: zeros \: = 2 \\ \\ sum \: of \: product \: of \: zeros \: = \frac{c}{a} \\ \\ \frac{5}{1} \\ \\ sum \: of \: product \: of \: zeros \: = 5$

Answered by suhaskumar123

Answer:

\begin{lgathered}for \: cubic \: polynomial \\ \\ p(x) = {x}^{3} - 4 {x}^{2} + 5x - 2 = 0 \\ \\ sum \: of \: zeros \: = \frac{ - b}{a} = \frac{ - (- 4)}{1} = + 4 \\ \\ sum \: of \: zeros \: = 4 \\ \\ product \: of \: zeros \: = \frac{ - d}{a} = \frac{ - (- 2)}{1} \\ \\ product \: of \: zeros \: = 2 \\ \\ sum \: of \: product \: of \: zeros \: = \frac{c}{a} \\ \\ \frac{5}{1} \\ \\ sum \: of \: product \: of \: zeros \: = 5\end{lgathered}

forcubicpolynomial

p(x)=x

−4x

+5x−2=0

sumofzeros=

−b

−(−4)

=+4

sumofzeros=4

productofzeros=

−d

−(−2)

productofzeros=2

sumofproductofzeros=

sumofproductofzeros=5

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factories the following cubic polynomialP(x) = x^3 - 4x^2+5x-2​

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factories the following cubic polynomial
P(x) = x^3 - 4x^2+5x-2